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BTAPDFName:
![]() The probability mass function of the Borel-Tanner distribution is
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with The mean and variance of the Borel-Tanner distribution are
![]() variance = ![]()
<SUBSET/EXCEPT/FOR qualification> where <x> is a positive integer variable, number, or parameter; <lambda> is a number or parameter in the range (0,1) that specifies the first shape parameter; <k> is a number or parameter denoting a positive integer that specifies the first shape parameter; <y> is a variable or a parameter where the computed Borel-Tanner pdf value is stored; and where the <SUBSET/EXCEPT/FOR qualification> is optional.
LET Y = BTAPDF(X1,0.3,2) PLOT BTAPDF(X,0.3,2) FOR X = 2 1 20
LET K = <value> LET LAMBDA = <value> LET Y = BOREL-TANNER RANDOM NUMBERS FOR I = 1 1 N BOREL TANNER PROBABILITY PLOT Y BOREL TANNER PROBABILITY PLOT Y2 X2 BOREL TANNER PROBABILITY PLOT Y3 XLOW XHIGH To obtain the maximum likelihood estimate of lambda assuming that k is known, enter the command
BOREL TANNER MAXIMUM LIKELIHOOD Y2 X2 The maximum likelihood estimate is
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with
For a given value of k, generate an estimate of
LET LAMBDA1 = <value> LET LAMBDA2 = <value> BOREL TANNER KS PLOT Y BOREL TANNER KS PLOT Y2 X2 BOREL TANNER KS PLOT Y3 XLOW XHIGH BOREL TANNER PPCC PLOT Y BOREL TANNER PPCC PLOT Y2 X2 BOREL TANNER PPCC PLOT Y3 XLOW XHIGH The default values of LAMBDA1 and LAMBDA2 are 0.05 and 0.95, respectively. The value of k should typically be set to the minimum value of the data. Due to the discrete nature of the percent point function for discrete distributions, the ppcc plot will not be smooth. For that reason, if there is sufficient sample size the KS PLOT (i.e., the minimum chi-square value) is typically preferred. Also, since the data is integer values, one of the binned forms is preferred for these commands. To generate a chi-square goodness of fit test, enter the commands
LET LAMBDA = <value> BOREL-TANNER CHI-SQUARE GOODNESS OF FIT Y2 X2 BOREL-TANNER CHI-SQUARE GOODNESS OF FIT Y3 XLOW XHIGH
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![]() ![]() ![]() ![]() the resulting distribution is referred to as the Lagrange-Poisson distribution (or the Consul generalized Poisson distribution). This distribution has probability mass function
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Johnson, Kotz, and Kemp (1992), "Univariate Discrete Distributions", Second Edition, Wiley, pp. 394-396.
let k = 2 let lambda = 0.8 let y = borel tanner random numbers for i = 1 1 500 . let y3 xlow xhigh = integer frequency table y class lower 1.5 class width 1 let amax = maximum y let amax2 = amax + 0.5 class upper amax2 let y2 x2 = binned y . let k = minimum y borel tanner mle y relative histogram y2 x2 limits freeze pre-erase off line color blue plot btapdf(x,lambdaml,k) for x = 2 1 amax limits pre-erase on line color black let lambda = lambdaml borel tanner chi-square goodness of fit y3 xlow xhigh case asis justification center move 50 97 text Lambda = ^lambdaml move 50 93 text Minimum Chi-Square = ^minks, 95% CV = ^cutupp95 . let k = 2 label case asis x1label Lambda y1label Minimum Chi-Square let lambda1 = 0.5 let lambda2 = 0.9 borel tanner ks plot y3 xlow xhigh let lambda = shape borel tanner chi-square goodness of fit y3 xlow xhigh case asis justification center move 50 97 text Lambda = ^lambda move 50 93 text Minimum Chi-Square = ^minks, 95% CV = ^cutupp95 ![]() CHI-SQUARED GOODNESS-OF-FIT TEST NULL HYPOTHESIS H0: DISTRIBUTION FITS THE DATA ALTERNATE HYPOTHESIS HA: DISTRIBUTION DOES NOT FIT THE DATA DISTRIBUTION: BOREL-TANNER SAMPLE: NUMBER OF OBSERVATIONS = 500 NUMBER OF NON-EMPTY CELLS = 27 NUMBER OF PARAMETERS USED = 2 TEST: CHI-SQUARED TEST STATISTIC = 17.10083 DEGREES OF FREEDOM = 24 CHI-SQUARED CDF VALUE = 0.155670 ALPHA LEVEL CUTOFF CONCLUSION 10% 33.19624 ACCEPT H0 5% 36.41503 ACCEPT H0 1% 42.97982 ACCEPT H0 ![]() CHI-SQUARED GOODNESS-OF-FIT TEST NULL HYPOTHESIS H0: DISTRIBUTION FITS THE DATA ALTERNATE HYPOTHESIS HA: DISTRIBUTION DOES NOT FIT THE DATA DISTRIBUTION: BOREL-TANNER SAMPLE: NUMBER OF OBSERVATIONS = 500 NUMBER OF NON-EMPTY CELLS = 27 NUMBER OF PARAMETERS USED = 2 TEST: CHI-SQUARED TEST STATISTIC = 16.33608 DEGREES OF FREEDOM = 24 CHI-SQUARED CDF VALUE = 0.124435 ALPHA LEVEL CUTOFF CONCLUSION 10% 33.19624 ACCEPT H0 5% 36.41503 ACCEPT H0 1% 42.97982 ACCEPT H0
Date created: 6/5/2006 |